I have the following question:
A baker filled a measuring cup with $3/4$ cup of water. He poured $1/2$ of the water into the batter, and then spilled $1/8$ of the water on the floor.
How much water will the baker need to add to what is left in the cup to have 50% more than what he started with?
Now, these are the possible answers given by the question:
- $1/8$ cup.
- $3/8$ cup.
- $1/4$ cup.
- $1/2$ cup.
- $7/8$ cup.
Here's what I did:
We start with $$3/4 \rightarrow 6/8,$$ after pouring the water into the batter $$6/8 - 1/2 \implies 6/8 - 4/8 = 2/8$$ and after spilling the water $$2/8 - 1/8 = 1/8.$$
Now, to find how much we need to add, we add $50\%$ of $3/4$ to the original $3/4$, that is $$(1/2)(3/4) + 3/4 = 3/8 + 6/8 = 9/8.$$
So the total amount of water we need to add is $$9/8 - 1/8 = 8/8.$$ But as you can see this is not one of the possible options.
I don't know if I'm doing something wrong or if the answers are incorrect, I suspect that I'm reading something wrong and there's something I'm just not seeing. I ask for your help with this. Thanks in advance.
You may be reading the question wrong. Try to solve it again using a different wording, so instead of subtracting $\frac{1}{2}$ cup of the water try subtracting half of the total amount of water, and try the same with the 1/8.