Statement is $\exists I = (x_o - \frac{1}{n}, x_o + \frac{1}{n}), n \in \mathbb N$, s.t $f(x) > 0 $ $\forall x \in I$
When negating the part after "such that", would it be
$f(x) \leq 0$ $\forall x \in I $ or $\exists x \in I$ s.t $f(x) \leq 0$ ?
Statement is $\exists I = (x_o - \frac{1}{n}, x_o + \frac{1}{n}), n \in \mathbb N$, s.t $f(x) > 0 $ $\forall x \in I$
When negating the part after "such that", would it be
$f(x) \leq 0$ $\forall x \in I $ or $\exists x \in I$ s.t $f(x) \leq 0$ ?
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