Basic root inequality proof: sum of 2 roots above 1

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this is the first time I upload to this site. I got this in my differential and integral mathematics class for physicists:

for $n,m∈\mathbb{N} $ prove:

$$\frac{1}{\sqrt[n]{1+m}}+\frac{1}{\sqrt[m]{1+n}}\ge 1$$

I'm pretty early in the course so I'd preffer a simple answer with use of mainy basic inequalities (the triangle inequality, bernoulis inequality, other simple and basic subjects).