Basic trigonometry - Find length of side when knowing one side length and the opposite angle

Question

I have this basic trigonometry question of finding the length of "x" in the triangle Finding X. I know one side of the triangle and the opposite angle, so I figured it should be a simple case of just filling in the equations of cosine. I've tried looking at other solutions of similar problems, but I can't wrap my head around how to apply their approach to my problem.

Sorry if this is way too basic, I notice it's been too long since I've used trig..

Answer 1

$$\tan \theta =\dfrac{\text{side opposite }\theta}{\text{side adjacent }\theta}$$

Here the $\text{side opposite }\theta$ to the angle of $6^{\circ}$ is $x$ and $\text{side adjacent }\theta$ is $3$.

$$\tan 6^{\circ}=\dfrac{x}{3}\implies x=3\tan6^{\circ}$$

You can leave it like that as $6^{\circ}$ is not a special angle, if however, you can use a calculator, simply feed in the expression to get $x \approx 0.315312705798$ and you're done.

Answer 2

Use tangent: $\tan 6°=\frac{x}{3} \rightarrow x=3\tan 6° \approx 0.32$