I'm trying to Isolate DR in the function below. Was wondering if I got it correct.
$(1 + DR)^y$ = $(1 + N/C)^C$
My answer
$$Dr = e^{\ln(1 + N/C)^C \over y}$$
Sorry about that last line. eveyrthing in the bracket after exponential is making the exponential raised by that.
If $$(1+DR)^y = \left(1+\tfrac NC\right)^C$$ then $$DR = \left(1+\tfrac NC\right)^{\frac Cy} - 1$$