Basis for the subspace W orthogonal to a line

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Let $V$ be the vector space of polynomials of degree $≤2$ with inner product given by:

$\left \langle f,g \right \rangle=\int_{0}^{1}f(t)g(t)dt$

Let $f(t)=t+2$, $g(t)=t^{2}-2t-3$, and $h(t)=2t+1$. Find a basis for the subspace $W$ orthogonal to $h(t)$.

Picture can be found here! 1 I was able to do (a) and (b) and reckon I'd need to do (c) properly to make sure that my answer for (d) is correct. Thanks so much!

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Assuming you already have seen the Gram-Schmidt procedure, I'll give you a way to solve this problem. We know that the space of polynomials of degree $\leq 2$ is a three dimensional vector space over $\mathbb{R}$. We construct a basis for this space by taking your polynomial $h(t)$, and adding the polynomials $x^2$ and $1$, these polynomials are independent and thus gives a basis for the space of polynomials.

We are going to solve problem c) and d) at once by orthonormalizing this set of polynomials $\left\{2t+1,t^2,1\right\}$ using the GS procedure, lets call the resulting set $\left\{p_1,p_2,p_3\right\}$. By the theorem of GS, $p_1$ spans the same space as $h(t)$, and thus we have that the space generated by $p_2$ and $p_3$ is orthogonally to the space generated by $h(t)$ because of the dimension theorem, which says that $$\dim(V)=\dim(W)+\dim(W^{\perp})$$ Hope this helps!