I'm trying to prove that the function
$t(n) = \sqrt{n^2 - 10(n)} - n $
is equal to O(1) time complexity. I know that the function has a horizontal asymptote at 5, so for n>0, t(n)<5 i.e. c=5 and n0=0. However, unlike O(n) or O(n^2), I'm not sure how to formally prove this.
Observe \begin{align} \left|n-\sqrt{n^2-10n}\right| \leq \frac{10n}{n+\sqrt{n^2-10n}} \leq 10 \end{align} for all $n$.