My thought process to solving this is that 1011 & (~0 << 2) = 1011 & (1 << 2) = 1011 & 0100 = 0000. But my book says the answer is 1000, what am I doing wrong?
2025-01-13 00:14:04.1736727244
Binary operations 1011 & (~0 << 2)
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This is not really a mathematics question...
If we assume for example a 16 bit word size, then $\sim\!0=1111\,1111\,1111\,1111$ and $(\sim\!0 <\!< 2) = 1111\,1111\,1111\,1100$. The rest should be clear.