Binomial Expansion for n < 1

Question

Write Down the First 3 terms of $\sqrt[3]{1 + \frac{x}{8}}$
My First step : After Evaluation, I got $$\Bigl(\frac{1}{8}x + 1\Bigl)^\frac{1}{3}$$ but, $${{\frac{1}{3}} \choose {r} } = \text{undefined}$$
How am I supposed to do this or am I missing something crucial ?

Answer 1

$$\sqrt[3]{1 + \frac{x}{8}}=1+\bigg(\frac{\frac{1}{3}}{1!}\bigg)\bigg(\frac{x}{8}\bigg)^1+\bigg(\frac{\frac{1}{3}\times(\frac{1}{3}-1)}{2!}\bigg)\bigg(\frac{x}{8}\bigg)^2+\cdots=1+\frac{x}{24}-\frac{x^2}{576}+\cdots$$