Birkhoff-von Neumann Proof inequality explanation

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This is a consequence of $P_{i,j}\geq 0$ and the fact that the sum on the right runs over more elements. $$ \sum_{i \in U} \sum_{j \in N(U)}{N_{i,j}} \leq $$ $$ \sum_{i = 1}^n \sum_{j \in N(U)}{N_{i,j}} = $$ $$ \sum_{j \in N(U)} \sum_{i = 1}^n {N_{i,j}}. $$