Boolean Algebra simplification help

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A'B'CD' + A'BCD + AB'C'D + AB'CD + ABC'D'

I have tried using a k map and I got it down to AC'D' + A'B'CD' + A'BCD + AB'CD. Also I think AB'C'D + AB'CD can be simplified to ABD'

Trying to simplify this. Any help would be great!

Thanks