Boolean algebra - subtraction and inverse doubt

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How to simultaneously solve these boolean expressions?

A' + AB = 0

AB = AC

AB + AC' + CD = C'D

    where ' means conjugate.

So this might seem silly but:

a) I have never heard of subtraction in Boolean.

b) I have never heard of inverse (NOTE: Not to be confused with conjugate).

So, what I want to say is that if both "subtraction" and"inverse" DON'T exist in Boolean, how exactly does one solve above equations?

Thanks so much in advance!