$$AB'C'D+ABCD$$ $$=AD(B'C'+BC)$$ $$=AD$$
I have simplified this expression right but for some reason I still get the answer wrong. The expression $AD$ does not match the original truth table. Please help.
$$AB'C'D+ABCD$$ $$=AD(B'C'+BC)$$ $$=AD$$
I have simplified this expression right but for some reason I still get the answer wrong. The expression $AD$ does not match the original truth table. Please help.
Note that $B'C' \ne (BC)'$
$$AB'C'D + ABCD = AD(B'C' + BC) = AD((B+C)'+BC)$$