Can someone help me on this exercise ? Thanks!
2026-03-28 09:54:30.1774691670
Bounded & Norm space
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Hint
$$||Tf||_\infty=\sup_{s\in[0,2]}|Tf(s)|\le\sqrt{2}||f||_\infty$$
Take $f$ the function constant equal to $1$ and prove that $||T||=\sqrt 2$.