Associativity of an integral against a function with finite variation

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I'm studying continuous martingales and there is this thing which worries me:

Let $a$ be of finite variation and $f$ be $a$–integrable. Then the function $(f · a)$ is right-continuous and of finite variation, where $(f · a)$ is defined as

$$\int_0^tf(s)\mu_+(ds)-\int_0^tf(s)\mu_-(ds)$$

where $\mu_+((0,t])=\frac{V_a(t)+a(t)}{2}$ and $\mu_-((0,t])=\frac{V_a(t)-a(t)}{2}$

where $V_a(t)$ is the variation of $a$ on $(0,t)$.

My lecture notes claim that assosiativity, i.e. $g·(f·a)=(gf)·a$ follows "readily", but I can't see it - the problem is that if I try to evaluate $g·(f·a)$ I get stuck with using $V_{f.a}$ bit in the measure.

Any help is appreciated!