Brianchon's theorem states that when a hexagon is circumscribed around a conic section (a hexagon formed by six tangent lines of a conic section), its principal diagonals (those connecting opposite vertices) meet in a single point.
I'm thinking if this theorem can apply on a degenerate conic, e.g. 2 intersecting or parallel lines. So there is a weird question: how to define 6 tangent lines of 2 intersecting or parallel lines?
If we apply Pascal's theorem on degenerate conic, we get Pappus's theorem. Since Brianchon's theorem is the dual of Pascal's theorem, Brianchon's theorem ondegenerate conic should be the dual of Pappus's theorem mentioned here with below diagram:
Is there any relation between above diagram and 6 tangent lines of 2 intersecting or parallel lines? (Obviously 6 tangent lines are ABCabc, but where are tangent points and 2 intersecting or parallel lines?)

For a degenerate conic that is two intersecting lines, the tangents are the pencil of lines going through the intersection. So the only Brianchon hexagon will have vertices that are identical.
The diagram you present can be thought of as a Brianchon hexagon for the degenerate conic that is the two points $G$ and $H$. It is a line conic, i.e. a conic that is defined as the envelope of a set of tangents. The tangents in this case are the two pencils of lines going through $G$ and $H$. And $G$ and $H$ can be thought of as the points that are dual to the outer straight lines in Pappus' Theorem. The mapping of a point conic to a line conic is an essential part of the dualization of Pappus' Theorem.
The figure above is from Richter-Gilbert, Perspectives on Projective Geometry, pg 161 and shows a progression of line conics going from ellipse to hyperbola, going through the two point line conic.