The base of a triangle increases in length by $25$%. Its area stays the same. Evaluate by what percentage has its height decreased?
- My answer is $20$% whereas my teacher's answer is $80$%. The question looks simple but it really made me perplexed about it. Any help would be appreciated. Thanks!
area of triangle = Ar$\triangle$=${1\over2}*b*h$ ,
-where $b=$base lenght and $h=$height given , base increases by $25$% $ \implies b'=b+{b\over4}={5b\over4} $ ,$b'=$new base and $h'$=new height
-Ar$\triangle$=${1\over2}*b*h={1\over2}*{5b\over4}*h'\implies h'={4h\over5}$