I need to calculate the integral:
$$ \int_{|z| = 2} \sin(2\cos(z) - 1)^5 \text{dz} $$
For now I only got:
$$ \int_0^1 \sin(\cos(2e^{2\pi it}) - 1)^5 \cdot 4\pi i e^{2\pi it} \text{dt} $$
and can't find any good way to proceed. Thank you for any further help!
The answer is zero since the integrand is an entire function and hence for any closed curve integrates to zero. I doubt the intent of the questioner is for you to actually calculate it. In fact, the point is quite the opposite.