Hint: One you have computed the vector $v = x - y$, compute the square of the distance as
$$
\|x - y\|^2 = \|v\|^2 = \langle v,v \rangle = v^T\pmatrix{2&1&0\\1&2&-1\\0&-1&2}v.
$$
Because this is the square of the distance, you must find the square root of the resulting number to get your answer.
Hint: One you have computed the vector $v = x - y$, compute the square of the distance as $$ \|x - y\|^2 = \|v\|^2 = \langle v,v \rangle = v^T\pmatrix{2&1&0\\1&2&-1\\0&-1&2}v. $$ Because this is the square of the distance, you must find the square root of the resulting number to get your answer.