I guess that i could start by equating the denominator to $0$ solving it for roots. $$x^3-3ix^2+2x+2i=0$$ $$x(x^2-3ix+2)=-2i$$ But i have no idea how to continue calculating this integral. It will be great if someone could explain how to continue this question and a guide in solving complex integrals as such.
2026-02-22 19:52:10.1771789930
calculate $\int_{-\infty}^\infty\frac{e^{ix} \, dx}{x^3-3ix^2+2x+2i}$
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