Yes, but your answer is incomplete. Once you calculate $17 \times \log(0.9)$, you need to take the anti-log to get the actual value of $0.9^{17}$. Assuming your log was the natural log, you would calculate $e^{17 \times \log(0.9)}$ to get what you want.
Yes, but your answer is incomplete. Once you calculate $17 \times \log(0.9)$, you need to take the anti-log to get the actual value of $0.9^{17}$. Assuming your log was the natural log, you would calculate $e^{17 \times \log(0.9)}$ to get what you want.