I am trying to calculate the inverse of a given matrix but somewhere I have an error in my calculation that I cannot find
$$\begin{array}{ccc} && \left( \begin{array}{ccc|ccc} 1-i & 2 & 1+i & 1 & 0 & 0 \\ 0 & 1+3i & 1+4i & 0 & 1 & 0 \\ 4+i&6+2i&2+i & 0 & 0 & 1 \end{array} \right) \begin{array}{cl} | & \cdot\, (1+i)\\ &\\ |& \cdot\, (8-2i) \end{array}\\ &\leadsto& \left( \begin{array}{ccc|ccc} 2 & 2+2i & 2i & 1+i & 0 & 0 \\ 0 & 1+3i & 1+4i & 0 & 1 & 0 \\ 34&52+4i&18+4i & 0 & 0 & 8-2i \end{array} \right) \begin{array}{cl} &\\ &\\ |&-17\cdot I \end{array} \\ &\leadsto& \left( \begin{array}{ccc|ccc} 2 & 2+2i & 2i & 1+i & 0 & 0 \\ 0 & 1+3i & 1+4i & 0 & 1 & 0 \\ 0&18-30i&18-30i & -17-17i & 0 & 8-2i \end{array} \right) \begin{array}{cl} &\\ |&\cdot\,(1-3i)\\ |&\cdot\,(18+30i) \end{array}\\ &\leadsto& \left( \begin{array}{ccc|ccc} 2 & 2+2i & 2i & 1+i & 0 & 0 \\ 0 & 4 & 13+i & 0 & 1-3i & 0 \\ 0&1224&1224& 204-816i & 0 & 204+204i \end{array} \right) \begin{array}{cl} &\\ &\\ |& :\,102 \end{array} \\ &\leadsto& \left( \begin{array}{ccc|ccc} 2 & 2+2i & 2i & 1+i & 0 & 0 \\ 0 & 4 & 13+i & 0 & 1-3i & 0 \\ 0&12&12 & 2-8i & 0 & 2+2i \end{array} \right) \begin{array}{cl} &\\ &\\ |&-3\cdot II \end{array}\\ &\leadsto& \left( \begin{array}{ccc|ccc} 2 & 2+2i & 2i & 1+i & 0 & 0 \\ 0 & 4 & 13+i & 0 & 1-3i & 0 \\ 0&0&-27-3i & 2-8i & -3+9i & 2+2i \end{array} \right) \end{array} $$
Now i would "devide" by $\left(-27-3i\right)$ and then for example the second entry of the third line on the right sight should be $-i$ (see Wolfram Alpha) but obviously I get a different result. Can you spot any error in my calculations?
Here is an error that I found. In the step where you multiply row two by $1-3i$, the second row should become $(0,\ 10,\ 13+i)$. You have it as $(0,\ 4,\ 13+i)$.