Find the speed of $r(t)=(4t+3,5t−1,5−t)$ at $t=2$.
$\|v(t)\|=\|(4,5,-1)\|=(16+25+1)^{1/2}=(42)^{1/2}=6.48$
How should the $t=2$ be incorporated if there is no variable left when $r(t)$ is derived?
Find the speed of $r(t)=(4t+3,5t−1,5−t)$ at $t=2$.
$\|v(t)\|=\|(4,5,-1)\|=(16+25+1)^{1/2}=(42)^{1/2}=6.48$
How should the $t=2$ be incorporated if there is no variable left when $r(t)$ is derived?
The speed is constant; it has the same value for all $t$.