Calculating speed of a big wheel

Question

I have the question "A big wheel at a fairground has a radius of 23[m] and takes 5 mins to turn once. What speed does a point on the edge of the wheel have?."

I know that the speed of a point on the edge of the wheel is linear velocity and so to calculate this you use the equation

V = rw

Here is my working is the final answer correct ?

Answer 1

You know that $V=r\omega$ and $\omega=2\pi v$. Now all you need to do is apply the given data in the formula's:

$v$=1/300 (as $T=5 minutes$)

$\omega=2\pi v=2\pi {1/300}$.

$V=r\omega={23}*2\pi {1/300}$ which roughly turns out to be $0.5m/s$