Calculating speed of minute hand on a clock

Question

The minute hand on a clock is $12 \text{ cm}$ long. Calculate the speed of its free end.

Is the following correct ? I have already worked out its angular speed from the previous question.

$$v = \omega r \\ \omega = 1.75\times 10^{-3} \text{ rad s$^{-1}$} \\ r = 12\text{ cm} = 1200\text{ m}$$

$$\begin{align}\therefore v &= (1.75\times 10^{-3} \text{ rad s$^{-1}$})\times (1200\text{ m}) \\ \therefore v &= 2.1\text{ ms$^{-1}$}\end{align}$$

Answer 1

12 cm = 0.12 m, not 1200 m ,,,,,,,

Answer 2

The tip travels $2\pi\cdot12$ cm in one hour, hence $2\pi\cdot12/3600$ cm/s. (About $0.21$ mm/s.)

Answer 3

The angular speed of the minute hand of a clock is $\dfrac{2\pi}{3600} rad/s$ or $\dfrac{\pi}{1800} rad/s$.