I need to find the arc length from the function $$ y^{2}= - 2.6\times x$$
Will the result change if I replace the function with? $$x = \frac{y^{2}}{-2.6}$$ I also ask you to check my answer, I did it: $$\frac{y\times\sqrt{1+\frac{y^{2}}{1.69}}+\ln\mid\frac{y}{1.3}+\sqrt{1+\frac{y^{2}}{1.69}}\mid}{3}$$
