Calculating the determinant of a matrix.

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Let $A \in M_n(k)$ such that $A^3-A^2 + A - I_n =0$

1.) Prove that $A$ is invertible and determine $A^{-1}$

2.) Calculate $det(A)$

For the first question :

$A^3-A^2 + A - I_n =0$

$A(A^2-A + I_n) =I_n$

Hence $A^{-1}$ = $(A^2-A + I_n)$

For the 2nd question :

Assume that $x^3-x^2 + x - 1 $ is the minimal polynomial of $A$ .

which has 1 real root $x = 1$ which is the eigenvalue.

since the determinant is equal to the product of eigenvalues $det(A)=1$

However I'm not sure if my assumption is correct nor if i should prove that A is diagonalizable for the determinant to be equal to the product of the eigenvalues.

Thanks in advance.