Calculating time and velocity using vectors

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For my homework, I was given a set of river problems relating to vectors. What I am really struggling with is creating a diagram out of the given information as I always fail to make an accurate representation of the provided information.

As for an example, here is a question which I do not quite understand.

Here is the question

Mary leaves a dock, paddling her canoe at 3 m/s. She heads downstream at an angle of $30^\circ$ to the current, which is flowing with 4 m/s.

  1. How far downstream does Mary travel in 10s?
  2. What is the length of time required to cross the river if its width is 150m?

So, what I have tried to do is:

Since I know that the triangle is a right-angled (Would be greatly appreciated to know of a way to determine whether each triangle is right-angled or not since I only based this assumption on my diagram which again, in my opinion, isn't accurate.) I have tried plotting a diagram to visualize the question (You can see it here), and solving for side d using sin. However, I got that d = 3sin30, which when I tried finding the time using the formula d = vt, I got the wrong answer according to my textbook.

I really am lost, and I don't completely understand where I messed up. Could someone perhaps explain to me what I have done wrong? I am almost sure that I didn't draw the diagram correctly as I feel that the problem is with my understanding of the question.

Thanks a whole bunch!

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There are several assumptions/ misconceptions, you almost found. First one, there is no need for right angle. In fact, in your figure, for a right angle triangle the hypotenuse ($3$) must be greater than any of the sides (you have one with length $4$). So let's start from your figure, but you need to keep only the line denoting the motion of the canoe, at $30^\circ$ with respect to the current. If there would be no current, in one second the canoe will travel $3\sin 30^\circ$ meters in the direction across, and $3\cos 30^\circ$ down the river. If you add the current, it has no component in the perpendicular direction, so you still move $3\sin 30^\circ$, but in the downstream direction the canoe is traveling $3\cos 30^\circ+4$ meters. To draw the diagram, start with the speed of the canoe vector, as you have done in your figure, then from the end of that vector draw a vector of length $4$ in the downstream direction. To obtain the velocity with respect to the starting point just join the starting point with the end of the vector representing the current velocity. enter image description here