Calculus Apostol, 1.26 exercise 21 b

103 Views Asked by At

I don't know how to solve this with the absolute value.

Find the value of c: \[ \int_{0}^{c} |x(1-x)|dx=0 \]

Please, if possible, make a solution step-by-step. Thank you and sorry for the poor english.

1

There are 1 best solutions below

1
On BEST ANSWER

HINT:

If $c\le 1$, then $\frac{c^2}{2}-\frac{c^3}{3}=0$.

If $c>1$, then $\frac{1}{2}-\frac{1}{3}+\frac{c^3}{3}-\frac{c^2}{2}-\frac{1}{3}+\frac{1}{2}=0 \Rightarrow \frac{c^2}{2}-\frac{c^3}{3}=\frac{1}{3}$.

Now try it out.