This question is on my integral work.
These are the steps I have gone through;
i = 2sin (π/2)t
Sin (π/2) = 1.
= 2 x 1t
= 2t
∫ 2/2t^2
=t^2
Where do I go from here. Substitute t with the time in question (2), then put that answer in the original equation?
On
In general, the relation between charge and current can be described as $$i(t) = \frac{\mathrm{d}Q(t)}{\mathrm{d}t}$$ So if you want to compute the charge at a certain time, you would do something like $$Q(t) = \int_{0}^{t}i(\tau)\mathrm{d}\tau$$ From a physical perspective, both quantities need a multiplicative constant that is assigning a unit to the respective quantity. That should look like $\hat{\mathrm{I}}$ for the current and $\hat{\mathrm{Q}}$ for the charge. I mention this because by following your approach, you would assign a value of time in seconds $[s]$ to electrical charge which is measured in Coulombs $[C]$.
I assume that the current starts at $t=0$ and the units are seconds. It's not explicitly written in your assingment but it is important. I don't know if I read the integral correctly. There should be:
$$\int_0^22t = [t^2]_0^2 = 2^2-0^2=4$$