Calculus of logs: Find the value of k

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The equation of a line perpendicular to the curve $y = \log_e (2x − 1)$ has the equation $y = −2x + k$, where $k$ is a constant. Find the value of $k$, correct to $1$ decimal place.

I know that a perpendicular line has a gradient of $-1/m$ to the line that it is perpendicular with, but other than that I'm not even sure where to start with this question. Any suggestions would be appreciated. Thanks

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We are asked to find the point on the curve, where slope of normal is $-2$. We know that slope of normal is $-2$ if and only if slope of the tangent at that point is $\frac{1}{2}$. Now, $$\frac{dy}{dx}=\frac{2}{2x-1}$$ Hence, at the solution point, $x=\frac{5}{2}$. Hence, solving for $y$ coordinate, $$k-5=\ln{4}$$ Now, find the value of $k$ in decimals.

Hope it helps:)