Can a free module have invariant basis number if its ring doesn't?

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Is there a free $R$-module $M$ such that $M$ has invariant basis number (IBN), while $R$ does not have the IBN property?

My use of "invariant basis number" here (for modules) doesn't seem to be standard, but I just mean $M$ has a unique, well-defined rank. To rephrase my question, can there exist a free $R$-module $M$ such that

  1. Every basis of $M$ has the same cardinality.
  2. There exists a free $R$-module that has bases of different cardinalities.

Just curious, as I'm only first learning about IBN and don't know many examples yet.

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(I mention in passing the zero module, which is free and with a unique number of generators for any ring, but it is not really in the spirit of the question.)

Using Leavitt path algebras, it is possible to construct a ring such that $R^2\cong R^3$, and hence $R^2\cong R^n$ for all $n\geq 2$, but $R\ncong R^2$. (Here is another post about it.)

In that case, every cyclic free $R$ module has a unique rank, but free modules with more than one generator do not.

You're right that one shouldn't probably call this "invariant basis number for a module" but rather say that it's a free module "whose bases have a unique, finite size" or something like what you said.