Is a conformal transformation also a general coordinate transformation?

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As far as I understand, a general coordinate transformation is induced by a diffeomorphism $f:M\rightarrow M$ where $M$ is a manifold (which can locally be described with coordinates). So if $x:M\rightarrow \mathbb{R}^m$ is a coordinate map, then $y:=x\circ f$ is a new coordinate map after the coordinate transformation. One could locally express the new coordinates in terms of the old ones, writing $y=y(x)$. Is that right so far?

Now if such a diffeomorphism is applied to all points, it should induce an effect on the metric. Let's say $X,Y$ are vector fields (elements of the module of derivatives over the ring of smooth functions $C^\infty(M)$ over $M$) and $g$ is the metric tensor field (an element of the comodule of the module of vector fields which takes two vector fields back to $C^\infty(M)$) and $p$ is a point of $M$. Then, is it right to say that the diffeomorphism induces the change \begin{equation} f^*g(X,Y)|_p = g_p(f_* X_p, f_* Y_p)? \end{equation} I have also seen in another post an action defined on all objects as in \begin{equation} (f^*)^{(-1)}g(f_* X,f_* Y)|_p = g_p(X_p, Y_p), \end{equation} which would mean that any diffeo would leave $g(X,Y)$ invariant? If this is correct, then I am confused here because I don't yet understand why the action should include the inverse of the pull-back?

A conformal transformation is defined as a diffeomorphism that leaves the metric invariant up to a an overall factor, meaning that the diffeomorphism induces a pull-back of the metric that is conformally equivalent (equivalent up to an overall factor) to the old one. Does this mean \begin{equation} f^*g(X,Y)|_p=g_p(f_* X_p, f_* Y_p)=\Omega(p) g_p(X_p,Y_p)? \end{equation}

In that case, a conformal transformation would be a coordinate transformation that changes the metric only by an overall factor and is thus also a coordinate transformation?

But then a conformal invariance of some theory would not be special anymore in a covariant formulation which confuses me. Thus my understanding of the action of a transformation on the metric and the vector fields is probably wrong at some (or multiple) point(s). Would be great if you could help me to clarify that.

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This may not be a complete answer, but it's some perspective.

A conformal transformation should not be considered a diffeomorphism. A diffeomorphism is an isomorphism of manifolds, meaning defined everywhere on each manifold. It may have a local representation in a particular coordinate system, but it will be different at each location and in each coordinate system.

A conformal transformation is a map that takes a metric $g$ (in a particular coordinate system) to $\Omega g$, but it's precise form depends on the local coordinate system. It actually can't be a coordinate system transform, because the scalar curvature is not invariant under a conformal transformation.

Could a conformal transformation be the pullback of a diffeomorphism? I suppose the answer is yes, and one could use the conditions on the invariance of the scalar curvature to find such a thing.