Can a gaussian be expressed as a sum of sines or cosines?

109 Views Asked by At

I'm taking a quantum mechanics course in university right now and we're dealing with gaussian wave packets and I'm particularly interested in whether a gaussian can be expressed as a sum of sines or cosines (so that I could find the group and phase velocity of these wave packets)?

1

There are 1 best solutions below

0
On

Taking for example the function

$$f(x)=e^{-x^2}\tag{1}$$

which I believe can be evaluated as

$$f(x)=\underset{N, f\to\infty}{\text{lim}}\left(\sum\limits_{n=1}^N \frac{\mu(2 n-1)}{2 n-1} \left(\frac{3 F(0)}{8}\\+\sum _{k=1}^{2 f (2 n-1)} (-1)^k\, \cos\left(\frac{\pi k}{2 n-1}\right)\, F\left(\frac{k}{4 n-2}\right)\, \cos\left(\frac{\pi k x}{2 n-1}\right)\\-\frac{1}{4} \sum\limits_{k=1}^{4 f (2 n-1)} (-1)^k\, F\left(\frac{k}{8 n-4}\right)\, \cos\left(\frac{\pi k x}{4 n-2}\right)\right)\right)\tag{2}$$

where $\mu(n)$ is the Möbius function, the evaluation frequency $f$ in the two inner sums over $k$ is assumed to be a positive integer, and

$$F(\omega)=\mathcal{F}_x[f(x)](\omega)=\int\limits_{-\infty}^{\infty} e^{-x^2} e^{-2 \pi i \omega x} \, dx=\sqrt{\pi}\, e^{-\pi^2 \omega^2}\tag{3}$$

is the Fourier transform of $f(t)$.


My related MSO question provides information on the derivation of formula (2) above (which corresponds to formula (11) in my related MSO question).


Figures (1) to (3) below illustrate formula (2) for $f(x)=e^{-x^2}$ in orange overlaid on the blue reference function $f(x)$ where formula (2) is evaluated at $f=4$ and $N=10$. Since $f(x)$ is complex analytic I believe formula (2) actually converges globally for $x\in\mathbb{C}$.


Illustration of formula (2) for f(x)=e^{-x^2}

Figure (1): Illustration of formula (2) for $f(x)$ in orange overlaid on the blue reference function $f(x)$


Illustration of real part of formula (2) for f(1+i t)

Figure (2): Illustration of real part of formula (2) for $f(1+i t)$ in orange overlaid on the blue reference function $\Re(f(1+i t))$


Illustration of imaginary part of formula (2) for f(1+i t)

Figure (3): Illustration of imaginary part of formula (2) for $f(1+i t)$ in orange overlaid on the blue reference function $\Im(f(1+i t))$