I am looking at page 26 of Dummit and Foote, and I see the following statement discussing the presentation of $D_{2n} = \langle r, s\mid r^2=1, s^n=1, rs=sr^{-1} \rangle$.
...$D_{2n}$ has the relations $r^2=1, s^n=1, rs=sr^{-1}$. Moreover, these relations have the property that any other relation among the elements of $S = \{r, s \}$ can be deduced from these three.
My question is, is this true for all group presentations? That is, can any relation between elements of the generators be determined from the relations in the presentation?
My inclination is no; because a few lines below, Dummit and Foote say
...in an arbitrary presentation it may be extremely difficult (or even impossible) to tell when two elements of the group (expressed in terms of the given generators) are equal.
Yes! Sometimes, a group is defined by one of its presentations, so there's no other choice when that happens.
This is known as a decidability result. It's the word problem. Generally speaking, given two elements of a group given by a presentation, it is literally impossible to decide whether or not one is equal to another using a Turing machine in finite time.
But this does not mean that any and all relations between elements of a group cannot be determined by the relations of a presentation of that group.