I'm stuck with the following integral $$I=\int_{-\infty}^{\infty}\frac{e^{-az^{2}}}{e^{-b-iz}-1}dz$$ It seems to me there exists a clever contour which encloses the pole at $z=ib$ while being somehow equivalent to the real line. Maybe someone has any ideas?
2026-04-07 11:23:05.1775560985
Can anyone help with an improper integral.
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