Can Hilbert projection theorem be proved without AC?

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Hilbert projection theorem For every vector $x$ in a Hilbert space $H$ and every closed vector subspace $C$, there exists a unique vector $m\in C$ such that $x−m$ is orthogonal to $C$.

All proofs of this theorem that I know of use the axiom of countable choice.

Can Hilbert projection theorem be proved without AC or its weak form?

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