Can someone explain to me to find the disk of convergence of the Taylor Series for $\frac{3}{1+z}$.
I already found the Taylor series: $\frac{3}{2}[1-\frac{(z-1)}{2}+\frac{(z-1)}{2}^2-\frac{(z-1)}{2}^3...]$
Can someone explain to me to find the disk of convergence of the Taylor Series for $\frac{3}{1+z}$.
I already found the Taylor series: $\frac{3}{2}[1-\frac{(z-1)}{2}+\frac{(z-1)}{2}^2-\frac{(z-1)}{2}^3...]$
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