Can someone explain to me to find the disk of convergence of the Taylor Series $\frac{3}{1+z}$.

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Can someone explain to me to find the disk of convergence of the Taylor Series for $\frac{3}{1+z}$.

I already found the Taylor series: $\frac{3}{2}[1-\frac{(z-1)}{2}+\frac{(z-1)}{2}^2-\frac{(z-1)}{2}^3...]$