Theorem.
Let $E$ be a subset of $\mathbb{R}^n$.
Then, if $p\gt0$, $\int_E|f-f_k|^p\to0$, and $\displaystyle\int_E|f_k|^p\le{}M$ for all $k$, then $\displaystyle\int_E|f|^p\le{}M$.
For your information, $|\cdot|$ means a Lebesgue measure.
- There is a Theorem A, $$\int_E|f|^p=p\int_0^\infty\alpha^{p-1}w_{|f|}(\alpha)d\alpha$$ ,where $w(\alpha)=\left|\left(\mathbf{x}\in{}E:f(\mathbf{x})\gt\alpha\right\}\right|$
- Since $|f|\le|f-f_k|+|f_k|$ by the triangle inequality, $$\int_E|f|\le\int_E\left(|f-f_k|+|f_k|\right)=\int_E|f-f_k|+\int_E|f_k|$$
- From the Theorem A when $p=1$, $$\int_0^\infty w_{|f|}(\alpha)d\alpha \le \int_0^\infty w_{|f-f_k|}(\alpha)d\alpha + \int_0^\infty w_{|f_k|}(\alpha)d\alpha$$
- Since (?), $$w_{|f|}(\alpha) \le w_{|f-f_k|}(\alpha) + w_{|f_k|}(\alpha)$$
- Thus, \begin{align} \int_E|f|^p &= p\int_0^\infty\alpha^{p-1}w_{|f|}(\alpha)d\alpha \\ &\le p\int_0^\infty\alpha^{p-1}\left(w_{|f-f_k|}(\alpha) + w_{|f_k|}(\alpha)\right)d\alpha \\ &= p\int_0^\infty\alpha^{p-1} w_{|f-f_k|}(\alpha) d\alpha + p\int_0^\infty\alpha^{p-1} w_{|f_k|}(\alpha) d\alpha \\ &=\int_E|f-f_k|^p + \int_E|f_k|^p \end{align}
- Letting $k\to\infty$, $$\int_E|f|^p \le M$$
I do not understand how the third process causes the fourth process.
Also, I do not understand the last process.
We are proving that $\displaystyle\int_E|f|^p\le{}M$, not proving that $\displaystyle\int_E|f|^p\le{}M$ as $k\to\infty$.