I've always diagonalized matrices in this way
$$S^{-1}AS = D$$
where $D$ diagonal and the columns of $S$ are the (linearly independent) eigenvectors of $A$.
Could I instead do $SAS^{-1}$? Is there an obvious flaw to this multiplication?
Thanks,
2026-03-30 23:43:58.1774914238
Can the diagonalizing matrix be to the left of the matrix of interest?
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The $S$ of one approach is the $S^{-1}$ of the other.