T = {X ⊆ ℕ : X is finite} ∪ {X ⊆ ℕ : ℕ\X is finite}
x∧y = x∩y
x∨y = x∪y
x' = ℕ\x
Zero = ∅
One = ℕ
I think it is correct but I am not sure if the finite (or infinite) set can make influence in defining Boolean Algebra.
T = {X ⊆ ℕ : X is finite} ∪ {X ⊆ ℕ : ℕ\X is finite}
x∧y = x∩y
x∨y = x∪y
x' = ℕ\x
Zero = ∅
One = ℕ
I think it is correct but I am not sure if the finite (or infinite) set can make influence in defining Boolean Algebra.
In general, for any set $X$, the powerset $\mathcal{P}(X)$ together with the following operations is a Boolean algebra :
Here, $T$ is just a subalgebra of $\mathcal{P}(\mathbb{N})$ :
Hence, $T$ is a Boolean algebra.