Can this condition infer that the matrix is Hermite?

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$\boldsymbol{A^H A=AA^H}$ does this imply that $\boldsymbol{A}$ is Hermite matrix? Why?

$\boldsymbol{A^H}$ is the conjugate transpose of $\boldsymbol{A}$

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No, your condition means that the matrix is normal. Not all normal matrices are hermitian (for example, pick your favorite unitary matrix).

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Obviously counterexample: Skew-Hermitian matrices and unitary matrices.