$f: \mathbb{R}^{+} \rightarrow \mathbb{R}^{+}$
$f(x^2)=xf(x)$
$f(x+1)=f(x)+1$
Can this functional equation be solved ?
Perhaps obvious but what about $$f(x)=x?$$
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Perhaps obvious but what about $$f(x)=x?$$