Given $A$, $B$, and the $b$ angle I need to solve for $C$. The red line is perpendicular to side $A$.
I know that via the law of cosines I have:
$$C^2 = A^2 + B^2 - 2AB\,cos(d)$$
but I only have $b$, not $d$. Can this be solved at all?
Given $A$, $B$, and the $b$ angle I need to solve for $C$. The red line is perpendicular to side $A$.
I know that via the law of cosines I have:
$$C^2 = A^2 + B^2 - 2AB\,cos(d)$$
but I only have $b$, not $d$. Can this be solved at all?
You know the angle between $A$ and $C$ and can use this in the cosine formula to obtain a quadratic for $C$. This will have two solutions in general, and you should consider their geometric significance.