Let $X$ be a banach space with separable dual $X^{*}$.
Let $\{x_n\}$ be a bounded sequence of $X$.
Can we say that $ \{x_n \} $ admits a convergent subsequence ?
Let $X$ be a banach space with separable dual $X^{*}$.
Let $\{x_n\}$ be a bounded sequence of $X$.
Can we say that $ \{x_n \} $ admits a convergent subsequence ?
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This is false in general. Consider $X = \ell_2$. Then $X^\ast$ is separable and the sequence $(e_n)$ with
$$e_n = (\dots, 0, 0, 1, 0, 0, \dots)$$
(with $1$ on the $n$-th position) is a bounded one which clearly does not have a convergent subsequence.