The recurrence relation is given as follows:
$T(n) = 2T(\sqrt{n})+1$
$T(1) = 1$
I tried to solve it with recursion tree as follows:

But to find the number of levels that may occur, I have to solve:
$\sqrt[2^x]{n} = 1$
$2x=\log{_1}{n}$
$\log{1} = 0$
So I am stuck here and cant move further.
What I am doing wrong?
PS: I know we can solve this using master theorem. But I am specifically interested in solving this using recursion tree method.
You are looking at this recurrence relation:
$T(n) = 2T(\sqrt{n})+1$
$T(1) = 1$
Suppose T is a solution. Then we have $T(1) = 2T(1) + 1$, so $1 = 3$. That is, this recurrence relation has no solution.