Can we split up any lebesgue integral into sum of integrals?

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Hi I am confused on something. We defined the lebesgue integral of a general f in the following way: If $\int f^+ <\infty $ and $\int f^- < \infty$ then $\int f= \int f^+ - \int f^-. $

So basically if we have an integral like $\int f+g $ then we can only seperate it if both f and g are integrable?

Also if we have a certain integral of f over the real numbers, can we split that integral into the sum of integrals over sets $A_i$ whose union is the real numbers? Can we do this even if we dont know whether the function is integrable? Thanks!

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Note that functions that aren't lebesgue integrable may still sum to a lebesgue integrable function: just take any non-integrable $f$ and let $g = -f$; neither are lebesgue integrable, but their sum is the zero function, which is lebesgue integrable.

Furthermore, if $f$ is a complex valued lebesgue integrable map on a measure space $(X,\mathbf{M},\mu)$, then the map

$\tilde{\mu}: \mathbf{M} \to \mathbb{C} \,;\, E \mapsto \int_E fd\mu$

will be a complex measure on $\mathbf{M}$, which is to say that it is complex valued and countably additive. Consequently, if $A_1,A_2,... \in \mathbf{M}$ are pairwise disjoint measurable sets then

$\int_{\bigcup_iA_i} f d\mu = \tilde{\mu}\left( \bigcup_i A_i \right) = \sum_i \tilde{\mu}(A_i) = \sum_i \int_{A_i} f d\mu$