I'm working on some homework. With a simple yes or no if you have a right triangle ABC with B being the 90 degree angle and not a 45-45-90 triangle and you have the value of the hypotenuse and the right angle can you find...
- the lengths of both AB and BC?
- the angles of A and C?
using sine, cosine and tangent?
This is not really different from previous answers, but slightly more general. If you know the length of one side of a triangle and the size of the opposite angle, you know that the third angle lies on an arc of a circle. With a right-angle you know this is the full circle.
If $R$ is the circumradius, $a$ is the length of the side and $A$ the opposite angle, you have $\cfrac a{\sin A}=2R$
This relates also to the fact that in a fixed circle, the angle subtended by a chord is constant on each arc cut off by the chord.
Your problem is equivalent to "the angle in a semicircle is a right angle".