I am solving RSA algorithm wherein I have to find d by finding $7$ inverse modulo $480$. Please help in solving till end using extended euclidean algorithm
Using extended Euclidean Algorithm for finding inverse as follows:
$$480 = 7(68) + 4$$ $$68 = 4(17) + 0$$
Now, I am getting remainder 0 here. How shall I proceed ahead after this first step
$480 = 7*68 + 4$ so $4 = 480 - 7*68$
$7 = 4 + 3$ so $3 = 7-4$
$4 = 3 + 1$ so $1 = 4 - 3$
So $1 = 4-3=$
$(480 - 7*68) - (7-4)=$
$(480-7*68) - (7-(480 - 7*68))=$
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So how do you solve $7k \equiv 1 \pmod{480}$?