I was working on a question in the context of integration.
The question had a step where:
$-2 \cos(\pi^3) - (-2\cos(0))$
which simplifies and was left as:
$ -2(\cos(\pi^3) -1)$
or
$2-2\cos(\pi^3)$
If is $\pi$ equal to 180 degrees radians:
Can you cube $\pi$ so that it would be $5832000$ degrees radians, and use it to simplify the $\cos(\pi^3)$ further? Then, is it correct that $\cos(180^3) = 1$?
So, the final answer is $0$?
That is not how it works. That is like saying $1 = 24$ because $1$ day is $24$ hours. Degrees and radians are two different measurement units for angles. Note that $\pi$ is a number and does not literally equal $180$. But $\pi$ radians does equal $180^{\circ}$. Moreover, $1$ degree is $\dfrac{\pi}{180}$ radians, and $1$ radian is $\dfrac{180}{\pi}$ degrees.
If your integration is correct, then $-2\cos\left(\pi^{3}\right)-\left(-2\cos\left(0\right)\right)$ just simplifies to $2-2\cos\left(\pi^{3}\right)$.